//===----------------------------------------------------------------------===// // // The LLVM Compiler Infrastructure // // This file is dual licensed under the MIT and the University of Illinois Open // Source Licenses. See LICENSE.TXT for details. // //===----------------------------------------------------------------------===// // <tuple> // template <class... Types> class tuple; // template <class... UTypes> // tuple& operator=(tuple<UTypes...>&& u); // UNSUPPORTED: c++98, c++03 #include <tuple> #include <string> #include <memory> #include <utility> #include <cassert> struct B { int id_; explicit B(int i= 0) : id_(i) {} virtual ~B() {} }; struct D : B { explicit D(int i) : B(i) {} }; struct E { E() = default; E& operator=(int) { return *this; } }; int main() { { typedef std::tuple<long> T0; typedef std::tuple<long long> T1; T0 t0(2); T1 t1; t1 = std::move(t0); assert(std::get<0>(t1) == 2); } { typedef std::tuple<long, char> T0; typedef std::tuple<long long, int> T1; T0 t0(2, 'a'); T1 t1; t1 = std::move(t0); assert(std::get<0>(t1) == 2); assert(std::get<1>(t1) == int('a')); } { typedef std::tuple<long, char, D> T0; typedef std::tuple<long long, int, B> T1; T0 t0(2, 'a', D(3)); T1 t1; t1 = std::move(t0); assert(std::get<0>(t1) == 2); assert(std::get<1>(t1) == int('a')); assert(std::get<2>(t1).id_ == 3); } { D d(3); D d2(2); typedef std::tuple<long, char, D&> T0; typedef std::tuple<long long, int, B&> T1; T0 t0(2, 'a', d2); T1 t1(1, 'b', d); t1 = std::move(t0); assert(std::get<0>(t1) == 2); assert(std::get<1>(t1) == int('a')); assert(std::get<2>(t1).id_ == 2); } { typedef std::tuple<long, char, std::unique_ptr<D>> T0; typedef std::tuple<long long, int, std::unique_ptr<B>> T1; T0 t0(2, 'a', std::unique_ptr<D>(new D(3))); T1 t1; t1 = std::move(t0); assert(std::get<0>(t1) == 2); assert(std::get<1>(t1) == int('a')); assert(std::get<2>(t1)->id_ == 3); } { // Test that tuple evaluates correctly applies an lvalue reference // before evaluating is_assignable (ie 'is_assignable<int&, int&&>') // instead of evaluating 'is_assignable<int&&, int&&>' which is false. int x = 42; int y = 43; std::tuple<int&&, E> t(std::move(x), E{}); std::tuple<int&&, int> t2(std::move(y), 44); t = std::move(t2); assert(std::get<0>(t) == 43); assert(&std::get<0>(t) == &x); } }