// Copyright (c) 2009 The Chromium Authors. All rights reserved. // Use of this source code is governed by a BSD-style license that can be // found in the LICENSE file. #ifndef BASE_LINKED_LIST_H_ #define BASE_LINKED_LIST_H_ #pragma once // Simple LinkedList type. (See the Q&A section to understand how this // differs from std::list). // // To use, start by declaring the class which will be contained in the linked // list, as extending LinkNode (this gives it next/previous pointers). // // class MyNodeType : public LinkNode<MyNodeType> { // ... // }; // // Next, to keep track of the list's head/tail, use a LinkedList instance: // // LinkedList<MyNodeType> list; // // To add elements to the list, use any of LinkedList::Append, // LinkNode::InsertBefore, or LinkNode::InsertAfter: // // LinkNode<MyNodeType>* n1 = ...; // LinkNode<MyNodeType>* n2 = ...; // LinkNode<MyNodeType>* n3 = ...; // // list.Append(n1); // list.Append(n3); // n3->InsertBefore(n3); // // Lastly, to iterate through the linked list forwards: // // for (LinkNode<MyNodeType>* node = list.head(); // node != list.end(); // node = node->next()) { // MyNodeType* value = node->value(); // ... // } // // Or to iterate the linked list backwards: // // for (LinkNode<MyNodeType>* node = list.tail(); // node != list.end(); // node = node->previous()) { // MyNodeType* value = node->value(); // ... // } // // Questions and Answers: // // Q. Should I use std::list or base::LinkedList? // // A. The main reason to use base::LinkedList over std::list is // performance. If you don't care about the performance differences // then use an STL container, as it makes for better code readability. // // Comparing the performance of base::LinkedList<T> to std::list<T*>: // // * Erasing an element of type T* from base::LinkedList<T> is // an O(1) operation. Whereas for std::list<T*> it is O(n). // That is because with std::list<T*> you must obtain an // iterator to the T* element before you can call erase(iterator). // // * Insertion operations with base::LinkedList<T> never require // heap allocations. // // Q. How does base::LinkedList implementation differ from std::list? // // A. Doubly-linked lists are made up of nodes that contain "next" and // "previous" pointers that reference other nodes in the list. // // With base::LinkedList<T>, the type being inserted already reserves // space for the "next" and "previous" pointers (base::LinkNode<T>*). // Whereas with std::list<T> the type can be anything, so the implementation // needs to glue on the "next" and "previous" pointers using // some internal node type. namespace base { template <typename T> class LinkNode { public: LinkNode() : previous_(0), next_(0) {} LinkNode(LinkNode<T>* previous, LinkNode<T>* next) : previous_(previous), next_(next) {} // Insert |this| into the linked list, before |e|. void InsertBefore(LinkNode<T>* e) { this->next_ = e; this->previous_ = e->previous_; e->previous_->next_ = this; e->previous_ = this; } // Insert |this| into the linked list, after |e|. void InsertAfter(LinkNode<T>* e) { this->next_ = e->next_; this->previous_ = e; e->next_->previous_ = this; e->next_ = this; } // Remove |this| from the linked list. void RemoveFromList() { this->previous_->next_ = this->next_; this->next_->previous_ = this->previous_; } LinkNode<T>* previous() const { return previous_; } LinkNode<T>* next() const { return next_; } // Cast from the node-type to the value type. const T* value() const { return static_cast<const T*>(this); } T* value() { return static_cast<T*>(this); } // Work around a Clang bug reported upstream: // http://llvm.org/bugs/show_bug.cgi?id=7974 // TODO(evanm): remove this and its sole caller. void set(LinkNode<T>* prev, LinkNode<T>* next) { previous_ = prev; next_ = next; } private: LinkNode<T>* previous_; LinkNode<T>* next_; }; template <typename T> class LinkedList { public: // The "root" node is self-referential, and forms the basis of a circular // list (root_.next() will point back to the start of the list, // and root_->previous() wraps around to the end of the list). LinkedList() { root_.set(&root_, &root_); } // Appends |e| to the end of the linked list. void Append(LinkNode<T>* e) { e->InsertBefore(&root_); } LinkNode<T>* head() const { return root_.next(); } LinkNode<T>* tail() const { return root_.previous(); } const LinkNode<T>* end() const { return &root_; } private: LinkNode<T> root_; }; } // namespace base #endif // BASE_LINKED_LIST_H_