/* The head-file for the Shark * by Alexander Schulz * * Does the following: * - get the memory layout from firmware. This can only be done as long as the mmu * is still on. * - switch the mmu off, so we have physical addresses * - copy the kernel to 0x08508000. This is done to have a fixed address where the * C-parts (misc.c) are executed. This address must be known at compile-time, * but the load-address of the kernel depends on how much memory is installed. * - Jump to this location. * - Set r8 with 0, r7 with the architecture ID for head.S */ #include <linux/linkage.h> #include <asm/assembler.h> .section ".start", "ax" .arch armv4 b __beginning __ofw_data: .long 0 @ the number of memory blocks .space 128 @ (startaddr,size) ... .space 128 @ bootargs .align __beginning: mov r4, r0 @ save the entry to the firmware mov r0, #0xC0 @ disable irq and fiq mov r1, r0 mrs r3, cpsr bic r2, r3, r0 eor r2, r2, r1 msr cpsr_c, r2 mov r0, r4 @ get the Memory layout from firmware adr r1, __ofw_data add r2, r1, #4 mov lr, pc b ofw_init mov r1, #0 adr r2, __mmu_off @ calculate physical address sub r2, r2, #0xf0000000 @ openprom maps us at f000 virt, 0e50 phys adr r0, __ofw_data ldr r0, [r0, #4] add r2, r2, r0 add r2, r2, #0x00500000 mrc p15, 0, r3, c1, c0 bic r3, r3, #0xC @ Write Buffer and DCache bic r3, r3, #0x1000 @ ICache mcr p15, 0, r3, c1, c0 @ disabled mov r0, #0 mcr p15, 0, r0, c7, c7 @ flush I,D caches on v4 mcr p15, 0, r0, c7, c10, 4 @ drain write buffer on v4 mcr p15, 0, r0, c8, c7 @ flush I,D TLBs on v4 bic r3, r3, #0x1 @ MMU mcr p15, 0, r3, c1, c0 @ disabled mov pc, r2 __copy_target: .long 0x08507FFC __copy_end: .long 0x08607FFC .word _start .word __bss_start .align __temp_stack: .space 128 __mmu_off: adr r0, __ofw_data @ read the 1. entry of the memory map ldr r0, [r0, #4] orr r0, r0, #0x00600000 sub r0, r0, #4 ldr r1, __copy_end ldr r3, __copy_target /* r0 = 0x0e600000 (current end of kernelcode) * r3 = 0x08508000 (where it should begin) * r1 = 0x08608000 (end of copying area, 1MB) * The kernel is compressed, so 1 MB should be enough. * copy the kernel to the beginning of physical memory * We start from the highest address, so we can copy * from 0x08500000 to 0x08508000 if we have only 8MB */ /* As we get more 2.6-kernels it gets more and more * uncomfortable to be bound to kernel images of 1MB only. * So we add a loop here, to be able to copy some more. * Alexander Schulz 2005-07-17 */ mov r4, #3 @ How many megabytes to copy __MoveCode: sub r4, r4, #1 __Copy: ldr r2, [r0], #-4 str r2, [r1], #-4 teq r1, r3 bne __Copy /* The firmware maps us in blocks of 1 MB, the next block is _below_ the last one. So our decrementing source pointer ist right here, but the destination pointer must be increased by 2 MB */ add r1, r1, #0x00200000 add r3, r3, #0x00100000 teq r4, #0 bne __MoveCode /* and jump to it */ adr r2, __go_on @ where we want to jump adr r0, __ofw_data @ read the 1. entry of the memory map ldr r0, [r0, #4] sub r2, r2, r0 @ we are mapped add 0e50 now, sub that (-0e00) sub r2, r2, #0x00500000 @ -0050 ldr r0, __copy_target @ and add 0850 8000 instead add r0, r0, #4 add r2, r2, r0 mov pc, r2 @ and jump there __go_on: adr sp, __temp_stack add sp, sp, #128 adr r0, __ofw_data mov lr, pc b create_params mov r8, #0 mov r7, #15